Find the magnitude of acceleration due to gravity at height of $10\, km$ from the surface of earth.

The acceleration due to gravity on the surface of earth is $g$. If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :

If a man at the equator would weigh $(3/5)^{th}$ of his weight, the angular speed of the earth is

At a certain depth "$d$" below surface of earth. value of acceleration due to gravity becomes four times that of its value at a height $3\,R$ above earth surface. Where $R$ is Radius of earth (Take $R =6400\,km$ ). The depth $d$ is equal to $…………\,km$

Weight of a body of mass m decreases by $1\%$ when it is raised to height $h$ above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is